Heat of Fusion Lab

Purpose: 

Determine the heat of fusion. 

Procedure: 

1) Start with 100 ml H2O at 50° C

2) Place into calorimeter (cup). Record temperature. 

3) Drop 2 to 3 ice cubes in. Stir don't run out of ice. 

4) Once temperature stabilizes around 0° C. Remove ice. 

5) Measure new volume. 

Data Table: 

Calculations: 

1) Mass of 100 ml H2O = 100g

2) Cal q= M x ^T x C  

q= 80g x 50° C x 4.18 KJ/mol

3) Determine q= 16,720 KJ

4) Mass of ice melted = 80g H2O

5) Mole of ice melted= 4.4 mole H2O

6) ^H fusion for ice = KJ/mol

    16,720/1000= 16.72 KJ/4.4 mole= 3.8 KJ/mol

Conclusion: 

^H= 6.01 KJ/mol 

^H= 3.8 KJ/mol 

Percent error: 36.7 percent off of the theoretical yield 

We had a lot of errors in our experiment the causes a large percent error. Some errors included waiting too long to put the ice cubes in so it was not at 100° C when we started. That means we did not need as much ice cubes. This caused a difference from the theoretical yield.